Jambmaths question:
if $P=\left( \begin{matrix} 1 & 0 & -1 \\ 3 & 4 & 5 \\ -1 & 0 & 1 \\\end{matrix} \right)$, then $\left| P \right|$ is
Option A:
4
Option B:
8
Option C:
– 8
Option D:
0
Jamb Maths Solution:
$\begin{align} & \left| P \right|=\left| \begin{matrix} 1 & 0 & -1 \\ 3 & 4 & 5 \\ -1 & 0 & 1 \\\end{matrix} \right| \\ & \left| P \right|=1\left| \begin{matrix} 4 & 5 \\ 0 & 1 \\\end{matrix} \right|-0\left| \begin{matrix} 3 & 5 \\ -1 & 1 \\\end{matrix} \right|-1\left| \begin{matrix} 3 & 4 \\ -1 & 0 \\\end{matrix} \right| \\ & \left| P \right|=1(4-0)-0(3+5)-1(0+8) \\ & \left| P \right|=4-0-4=0 \\\end{align}$
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