Jambmaths question:
Factorize completely $ac-2bc-{{a}^{2}}+4{{b}^{2}}$
Option A:
$(a-2b)(c-a-2b)$
Option B:
$(a-2b)(c+a+2b)$
Option C:
$(a-2b)(c-a+2b)$
Option D:
$(a-2b)((c+a-2b)$
Jamb Maths Solution:
$\begin{align} & ac-2bc-{{a}^{2}}+4{{b}^{2}}=c(a-2b)(-a+2b)(a+2b) \\ & =c(a-2b)-1(a-2b)(a+2b) \\ & =(a-2b)\left[ c-(a+2b) \right] \\ & =(a-2b)(c-a-2b) \end{align}$
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