Jambmaths question:
Simplify $\frac{\sqrt{12}-\sqrt{3}}{\sqrt{12}+\sqrt{3}}$
Option A:
$\tfrac{1}{3}$
Option B:
1
Option C:
0
Option D:
$\tfrac{3}{5}$
Jamb Maths Solution:
$\frac{\sqrt{12}-\sqrt{3}}{\sqrt{12}+\sqrt{3}}=\frac{2\sqrt{3}-\sqrt{3}}{2\sqrt{3}+\sqrt{3}}=\frac{\sqrt{3}}{3\sqrt{3}}=\frac{1}{3}$
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