Jambmaths question:
Three boys shard some oranges. The first received $\tfrac{1}{3}$of the oranges and second received $\tfrac{2}{3}$ of the remainder. If the third boy received the remaining 12 oranges, how many oranges did they share?
Option A:
42
Option B:
48
Option C:
54
Option D:
60
Jamb Maths Solution:
Let all the oranges be x
The first boy took$\tfrac{1}{3}x$, what is left is $\tfrac{2}{3}x$
The second boy took $\tfrac{2}{3}\times \tfrac{2}{3}x=\tfrac{4}{9}x$
The third boy will have $x-\left( \tfrac{1}{3}x+\tfrac{4}{9}x \right)=x-\tfrac{7}{9}x=\tfrac{2x}{9}$
That is $\tfrac{2x}{9}$ represent 12 oranges
The total oranges will be $x=\frac{12\times 9}{2}=54$
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