Jambmaths question:
What is mean deviation of 3, 5, 8, 11, 12 and 21?
Option A:
60
Option B:
10
Option C:
4.7
Option D:
3.7
Jamb Maths Solution:
$\begin{align} & mean=\overline{x}=\frac{3+5+8+11+12+21}{6}=10 \\ & \text{Deviation from mean}= \\ & =\tfrac{\left| 3-10 \right|+\left| (5-10) \right|+\left| (8-10) \right|+\left| (11-10) \right|+\left| (12-10) \right|+\left| (21-10) \right|}{6} \\ & =\frac{7+5+2+1+2+11}{6} \\ & =\frac{28}{6}\approx 4.7 \\\end{align}$
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