Jambmaths question:
A final requires that a student answer 4 out 6 questions. In how many ways can this be done?
Option A:
30
Option B:
20
Option C:
15
Option D:
45
Jamb Maths Solution:
$^{6}{{C}_{4}}=\frac{6!}{4!(6-4)!}=\frac{6!}{4!2!}=\frac{6\times 5\times 4!}{4!\times 2!}=15$
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Year of Exam:
