Jambmaths question:
If ${{\log }_{10}}2=0.3010$ and${{\log }_{10}}3=0.4771$, evaluate ${{\log }_{10}}4.5$
Option A:
0.4471
Option B:
0.3010
Option C:
0.6532
Option D:
0.9542
Jamb Maths Solution:
$\begin{align} & {{\log }_{10}}4.5={{\log }_{10}}\tfrac{9}{2} \\ & ={{\log }_{10}}{{3}^{2}}-{{\log }_{10}}2 \\ & =2\log 3-{{\log }_{10}}2 \\ & =2(0.4771)-0.3010 \\ & =0.9542-0.3010 \\ & =0.6532 \end{align}$
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