Jambmaths question:
A father decided to give 20% of his monthly income to his three children as their monthly allowance. The eldest child got 45% of the allowance and the youngest got 25%. How much was the father’s monthly income, if the second child got N3000.
Option A:
N50,000
Option B:
N33,000
Option C:
N60,000
Option D:
N45,000
Jamb Maths Solution:
Let the father salary be x
20% of x = 0.20x
The eldest child got 45% of 0.20x
That is $\tfrac{45}{100}\times 0.20x=0.09x$
The youngest child got 25% of 0.20x
That is $\tfrac{25}{100}\times 0.20x=0.05x$
The third child share will be $0.20x-(0.09+0.05x)=0.06x$
If 0.06x represent N3000. Then
$x=\frac{N3000}{0.06}=N50,000$
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