Jambmaths question:
A point P moves such that it is equidistance from Q and R. Find QR when PR =8cm and $\angle PRQ={{30}^{o}}$
Option A:
$4\sqrt{3}$cm
Option B:
8cm
Option C:
$8\sqrt{3}$cm
Option D:
4cm
Jamb Maths Solution:
$\cos {{30}^{\circ }}=\frac{x}{8}$
$x=8\cos {{30}^{o}}=4\sqrt{3}cm$
RQ = 2x (P is the perpendicular bisector of RQ}
RQ =$2\times 4\sqrt{3}cm=8\sqrt{3}cm$
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