Jambmaths question:
Find the value of θ in the diagram above
Option A:
100o
Option B:
120o
Option C:
30o
Option D:
60o
Jamb Maths Solution:
$\begin{align} & \cos C=\frac{{{c}^{2}}-{{a}^{2}}-{{b}^{2}}}{-2ab} \\ & \cos C=\frac{{{\left( \sqrt{3}t \right)}^{2}}-{{t}^{2}}-{{t}^{2}}}{-2(t)(t)} \\ & \cos C=\frac{3{{t}^{2}}-2{{t}^{2}}}{-2{{t}^{2}}}=\frac{{{t}^{2}}}{2{{t}^{2}}}=\frac{1}{2} \\ & C={{\cos }^{-1}}(-\tfrac{1}{2})=-{{60}^{o}}={{180}^{\circ }}-{{60}^{\circ }}={{120}^{\circ }} \\\end{align}$
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