Jambmaths question:
Evaluate the inequality $\frac{x}{2}+\frac{3}{4}\le \frac{5x}{6}-\frac{7}{12}$
Option A:
$x\le 3$
Option B:
$x\ge -3$
Option C:
$x\le -4$
Option D:
$x\ge 4$
Jamb Maths Solution:
$\begin{align} & \frac{x}{2}+\frac{3}{4}\le \frac{5x}{6}-\frac{7}{12} \\ & \frac{x}{2}-\frac{5x}{6}\le -\frac{7}{12}-\frac{3}{4} \\ & \frac{3x-5x}{6}\le \frac{-9-7}{12} \\ & \frac{-2x}{6}\le -\frac{16}{12} \\ & \frac{-x}{3}\le -\frac{4}{3} \\ & x\ge 4 \\\end{align}$
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