Jambmaths question:
Simplify $\frac{1}{\sqrt{3}+2}$
Option A:
$2-\sqrt{3}$
Option B:
$-2-\sqrt{3}$
Option C:
$2+\sqrt{3}$
Option D:
$-2+\sqrt{3}$
Jamb Maths Solution:
$\frac{1}{\sqrt{3}+2}=\frac{1}{\sqrt{3}+2}\times \frac{\sqrt{3}-2}{\sqrt{3-2}}=\frac{\sqrt{3}-2}{3-4}=\frac{\sqrt{3}-2}{-1}=-\sqrt{3}+2=2-\sqrt{3}$
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