Jambmaths question:
Rationalise$\frac{\sqrt{6}-\sqrt{4}}{\sqrt{6}+\sqrt{4}}$
Option A:
$5+2\sqrt{6}$
Option B:
$5-4\sqrt{6}$
Option C:
$5+4\sqrt{6}$
Option D:
$5-2\sqrt{6}$
Jamb Maths Solution:
$\begin{align} & \frac{\sqrt{6}-\sqrt{4}}{\sqrt{6}+\sqrt{4}}=\frac{\sqrt{6}-\sqrt{4}}{\sqrt{6}+\sqrt{4}}\times \frac{\sqrt{6}-\sqrt{4}}{\sqrt{6}-\sqrt{4}}=\frac{6+4-4\sqrt{6}}{6-4} \\ & \frac{\sqrt{6}-\sqrt{4}}{\sqrt{6}+\sqrt{4}}=\frac{10-4\sqrt{6}}{2}=5-2\sqrt{6} \\\end{align}$
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