Jambmaths question:
In how many can 9 people be seated if 3 chairs are available?
Jamb Maths Solution:
Possible arrangement = 9P3
$^{9}{{P}_{3}}=\frac{9!}{(9-3)!}=\frac{9!}{6!}=\frac{9\cdot 8\cdot 7\cdot 6!}{6!}=9\cdot 8\cdot 7=504ways$
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