Jambmaths question:
The range of the data k + 2, k – 3, k + 4, k – 2, k, k – 5, k + 3, k – 1 and k + 6
Option A:
10
Option B:
11
Option C:
6
Option D:
8
Jamb Maths Solution:
Highest magnitude = k + 6
Lowest magnitude = k – 5
$Range=(k+6)-(k-5)=11$
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