Jambmaths question:
Find the remainder when $3{{x}^{3}}+5{{x}^{2}}-11x+4$is divided by x + 3
Option A:
–4
Option B:
4
Option C:
1
Option D:
–1
Jamb Maths Solution:
$\begin{align} & \text{Let }f(x)=3{{x}^{3}}+5{{x}^{2}}-11x+4 \\ & \text{when }f(x)\text{ is divided by }x+3 \\ & \text{the remainder is }R=f(-3) \\ & f(-3)=3{{(-3)}^{3}}+5{{(-3)}^{2}}-11(-3)+4 \\ & f(-3)=-81+45+33+4 \\ & f(-3)=1 \\\end{align}$
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