$\begin{align}  & Area\text{ }of\text{ }the\text{ }rectangle=15\times 5c{{m}^{2}}=75c{{m}^{2}} \\ & Area of the semicircle=\frac{\pi {{r}^{2}}}{2}=\frac{22}{7}\times {{\left( \frac{5}{2} \right)}^{2}}\times \frac{1}{2}\approx 9.821c{{m}^{2}} \\ & Total\text{ }area=(75+9.821)c{{m}^{2}}\approx 84.8c{{m}^{2}}\text{   (1d}\text{.p)} \\\end{align}$