Jambmaths question:
In the diagram above $\angle OPQ$is
Option A:
90o
Option B:
53o
Option C:
36o
Option D:
26o
Jamb Maths Solution:
$\begin{align} & PO=OQ\text{ (radius of a circle)} \\ & O\overset{\wedge }{\mathop{P}}\,Q=P\overset{\wedge }{\mathop{Q}}\,O=x\text{ (Base angle of an issoceles }\Delta \text{)} \\ & \text{7}{{\text{4}}^{\text{o}}}+x+x={{180}^{\text{o}}} \\ & 2x={{106}^{\text{o}}} \\ & x={{53}^{\text{o}}} \\ & O\overset{\wedge }{\mathop{P}}\,Q={{53}^{\text{o}}} \\\end{align}$
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