Jambmaths question:
Simplify $(\sqrt{3}-\sqrt{2})(2\sqrt{3}+\sqrt{2})$
Option A:
$1-\sqrt{6}$
Option B:
$4-2\sqrt{6}$
Option C:
$4+2\sqrt{6}$
Option D:
.$4-\sqrt{6}$
Jamb Maths Solution:
$\begin{align} & (\sqrt{3}-\sqrt{2})(2\sqrt{3}+\sqrt{2})=6+\sqrt{6}-2\sqrt{6}-2 \\ & (\sqrt{3}-\sqrt{2})(2\sqrt{3}+\sqrt{2})=4-\sqrt{6} \\\end{align}$
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