waecmaths question:
The radii of the base of two cylindrical tins P and Q are r and 2r respectively. If the water level in P is 10cm high. What would be the height of the same quantity of water in Q
Option A:
2.5cm
Option B:
5.0cm
Option C:
7.5cm
Option D:
20.0cm
waecmaths solution:
$\begin{align} & V=\pi {{r}^{2}}(10)----cylinderP \\ & V=\pi {{(2r)}^{2}}h----cylinderQ \\ & \frac{V}{V}=\frac{10{{r}^{2}}}{4{{r}^{2}}h} \\ & 1=\frac{10}{4h} \\ & h=2.5cm \\\end{align}$
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