Jambmaths question:
What is the mean of the data $t,2t-1,t-2,2t-1,4t\text{ and }2t+2$
Option A:
$2t$
Option B:
$t-1$
Option C:
$\tfrac{2}{3}t+1$
Option D:
$t-\tfrac{1}{3}$
Jamb Maths Solution:
$\begin{align} & mean=\overline{x}=\frac{t+2t-1+t-2+2t-1+4t+2t+2t+2}{6} \\ & =\frac{12t-2}{6}=2t-\tfrac{1}{3} \end{align}$
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