Jambmaths question:
Solve the quadratic inequality ${{x}^{2}}-5x+6\ge 0$
Option A:
$x\le 2,x\ge 3$
Option B:
$x\le 3,x\ge 2$
Option C:
$x\le -2,x\ge -3$
Option D:
$x\le -3,x\ge 2$
Jamb Maths Solution:
${{x}^{2}}-5x+6\ge 0$
$(x-2)(x-3)\ge 0$
We need to determine the range for which the inequality is true
|
|
$x\le 2$
|
$2\le x\le 3$ |
$x\ge 3$ |
|
$(x-2)$ |
– |
+ |
+ |
|
$(x-3)$ |
– |
– |
+ |
|
$(x-2)(x-3)$ |
+ |
– |
+ |
The range is $x\le 2$or $x\ge 3$
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Year of Exam: