Jambmaths question:
In a basket, there are 6 grapes, 11 bananas and 13 oranges. If one fruit is chosen at random, what is the probability that the fruit is either a grape or a banana?
Option A:
$\frac{17}{30}$
Option B:
$\frac{11}{30}$
Option C:
$\frac{6}{30}$
Option D:
$\frac{5}{30}$
Jamb Maths Solution:
$\begin{align} & \text{Prob of choosing grape}=\frac{6}{30} \\ & \text{Prob of choosing banana}=\frac{11}{30} \\ & \text{Prob of either grape or banan}=\frac{6}{30}+\frac{11}{30}=\frac{17}{30} \\\end{align}$
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