Jambmaths question:
A binary operation $\oplus $ on real numbers is defined by $x\oplus y=xy+x+y$for any two real numbers x and y . The value of $(-\tfrac{3}{4})\oplus 6$ is
Option A:
$-\tfrac{9}{2}$
Option B:
$-\tfrac{3}{4}$
Option C:
$\tfrac{3}{4}$
Option D:
$\tfrac{45}{4}$
Jamb Maths Solution:
$\begin{align} & (-\tfrac{3}{4})\oplus 6=(-\tfrac{3}{4})(6)+(-\tfrac{3}{4})+6 \\ & =-\tfrac{9}{2}-\tfrac{3}{4}+6 \\ & =\tfrac{-18-3+24}{4} \\ & =\tfrac{3}{4} \end{align}$
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