Jambmaths question:
If $T=2\pi \sqrt{\frac{l}{g}}$make g the subject of formula
Option A:
$\frac{4\pi {{l}^{2}}}{T}$
Option B:
$\frac{4{{\pi }^{2}}l}{{{T}^{2}}}$
Option C:
$\frac{4{{\pi }^{2}}{{l}^{2}}}{{{T}^{2}}}$
Option D:
$\frac{2\pi \sqrt{l}}{T}$
Jamb Maths Solution:
$\begin{align} & T=2\pi \sqrt{\frac{l}{g}} \\ & \frac{T}{2\pi }=\sqrt{\frac{l}{g}}\text{ }\!\!\{\!\!\text{ Divide both sides by }2\pi \} \\ & \frac{{{T}^{2}}}{4{{\pi }^{2}}}=\frac{l}{g}\text{ }\!\!\{\!\!\text{ Square both sides }\!\!\}\!\!\text{ } \\ & \frac{g{{T}^{2}}}{4{{\pi }^{2}}}=l\text{ }\!\!\{\!\!\text{ Multiply both sides by }g\} \\ & g=\frac{4{{\pi }^{2}}l}{{{T}^{2}}}\text{ }\!\!\{\!\!\text{ Multiply both sides by }\tfrac{4{{\pi }^{2}}}{{{T}^{2}}}\} \\\end{align}$
Jamb Maths Topic:
Year of Exam: