Jambmaths question:
Solve the inequality for which $\frac{x+4}{3}-\frac{x-3}{2}<4$
Option A:
$x>7$
Option B:
$x<7$
Option C:
$x<-7$
Option D:
$x>-7$
Jamb Maths Solution:
$\begin{align} & \frac{x+4}{3}-\frac{x-3}{2}<4 \\ & \frac{2(x+4)-3(x-3)}{6}<4 \\ & \frac{2x+8-3x+9}{6}<4 \\ & \frac{-x+17}{6}<4 \\ & -x+17<24 \\ & -x<7 \\ & x>-7 \\\end{align}$
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