Jambmaths question:
If the locus of the points which are equidistant from P and Q meets line PQ at point N, then PN equals
Option A:
½NQ
Option B:
2NQ
Option C:
¼NQ
Option D:
NQ
Jamb Maths Solution:
Note: The locus of line PQ which is equidistant from P and Q is the perpendicular bisector of line PQ, So point N divides PQ into two equal parts.
PN = NQ
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