Jambmaths question:
Given that $\sqrt[3]{{{4}^{2x}}}=16$ find the value of x
Option A:
4
Option B:
6
Option C:
3
Option D:
2
Jamb Maths Solution:
$\begin{align} & \sqrt[3]{{{4}^{2x}}}=16 \\ & {{\left( {{4}^{2x}} \right)}^{\tfrac{1}{3}}}=16 \\ & {{4}^{\tfrac{2x}{3}}}=16 \\ & {{4}^{\frac{2x}{6}}}={{4}^{2}} \\ & \text{Equating the powers} \\ & \frac{2x}{3}=2 \\ & x=3 \\\end{align}$
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