Jambmaths question:
The sum of the interior angles of a pentagon is 6x + 6y. Find y in term of x
Option A:
y = 90 – x
Option B:
y = 150 – x
Option C:
y = 60 – x
Option D:
y = 120 – x
Jamb Maths Solution:
$\begin{align} & \text{Pentagon has 5 sides} \\ & \text{The total interior angles in a pentagon will be} \\ & (5-2)\times {{180}^{o}}={{540}^{o}}\text{ }\left| (n-2){{180}^{o}} \right. \\ & 6x+6y={{540}^{o}} \\ & x+y={{90}^{o}} \\ & y={{90}^{o}}-{{x}^{o}} \\\end{align}$
Jamb Maths Topic:
Year of Exam: