Jambmaths question:
Two dice are thrown. What is the probability that the sum of the number is divisible by 3
Option A:
$\frac{2}{3}$
Option B:
$\frac{1}{2}$
Option C:
$\frac{1}{3}$
Option D:
$\frac{1}{4}$
Jamb Maths Solution:
|
|
1 |
2 |
3 |
4 |
5 |
6 |
|
1 |
2 |
3 |
4 |
5 |
6 |
7 |
|
2 |
3 |
4 |
5 |
6 |
7 |
8 |
|
3 |
4 |
5 |
6 |
7 |
8 |
9 |
|
4 |
5 |
6 |
7 |
8 |
9 |
10 |
|
5 |
6 |
7 |
8 |
9 |
10 |
11 |
|
6 |
7 |
8 |
9 |
10 |
11 |
12 |
Numbers divisible by 3 are 12
Total possible outcome is 36
Probability (sum divisible by 3) = $\tfrac{12}{36}=\tfrac{1}{3}$
Jamb Maths Topic:
Year of Exam: