Jambmaths question:
The sum to infinity of the series $1+\tfrac{1}{3}+\tfrac{1}{9}+\tfrac{1}{27}+---$ is
Option A:
$\tfrac{11}{3}$
Option B:
$\tfrac{10}{3}$
Option C:
$\tfrac{5}{2}$
Option D:
$\tfrac{3}{2}$
Jamb Maths Solution:
$\begin{align} & a=1,\text{ }r=\tfrac{1}{3} \\ & {{S}_{\infty }}=\frac{a}{1-r}=\frac{1}{1-\tfrac{1}{3}} \\ & {{S}_{\infty }}=\frac{1}{\tfrac{2}{3}}=\frac{3}{2} \\\end{align}$
Jamb Maths Topic:
Year of Exam: