Jambmaths question:
If $\frac{dy}{dx}=2x-3$and y = 3 when x = 0. Find y in terms of x
Option A:
$2{{x}^{2}}-3x$
Option B:
${{x}^{2}}-3x$
Option C:
${{x}^{2}}-3x-3$
Option D:
${{x}^{2}}-3x+3$
Jamb Maths Solution:
$\begin{align} & \frac{dy}{dx}=2x-3 \\ & y=\int{(2x-3)dx} \\ & y=\frac{2{{x}^{2}}}{2}-3x+C \\ & \text{When }x=0,\text{ }y=3 \\ & 3={{0}^{2}}-3(0)+C \\ & C=3 \\ & \therefore y={{x}^{2}}-3x+3 \\\end{align}$
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