Jambmaths question:
Find the range ${\scriptstyle{}^{1}\!\!\diagup\!\!{}_{6}\;},{\scriptstyle{}^{1}\!\!\diagup\!\!{}_{3}\;},{\scriptstyle{}^{3}\!\!\diagup\!\!{}_{2}\;},{\scriptstyle{}^{8}\!\!\diagup\!\!{}_{9}\;}\text{ and }{\scriptstyle{}^{4}\!\!\diagup\!\!{}_{3}\;}$
Option A:
$\frac{3}{4}$
Option B:
$\frac{5}{6}$
Option C:
$\frac{7}{6}$
Option D:
$\frac{4}{3}$
Jamb Maths Solution:
$range=\frac{3}{2}-\frac{1}{6}=\frac{9-1}{6}=\frac{7}{6}$
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