Jambmaths question:
Find the value of t for which the determinant of the matrix$\left( \begin{matrix} t-4 & 0 & 0 \\ -1 & t+1 & 1 \\ 3 & 4 & t-2 \\\end{matrix} \right)$is zero
Jamb Maths Solution:
$\begin{align} & \left| \begin{matrix} t-4 & 0 & 0 \\ -1 & t+1 & 1 \\ 3 & 4 & t-2 \\\end{matrix} \right|=0 \\ & (t-4)\left| \begin{matrix} t+1 & 1 \\ 4 & t-2 \\\end{matrix} \right|+0+0=0 \\ & (t-4)[({{t}^{2}}-t-2)-4]=0 \\ & (t-4)({{t}^{2}}-t-6)=0 \\ & (t-4)(t-3)(t+2)=0 \\ & t=4,\text{ or }t=3\text{ or }t=-2 \\\end{align}$
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