In the diagram , O is the centre of the circle. Find the value of x
34o
29o
17o
14o
\[\begin{align} & \angle POR={{56}^{\circ }} \\ & \angle ROQ={{180}^{\circ }}-\angle POR \\ & \angle ROQ={{180}^{\circ }}-{{56}^{\circ }}={{124}^{\circ }} \\ & \left| RO \right|=\left| OQ \right|\text{ }\!\!\{\!\!\text{ radius of circle }\!\!\}\!\!\text{ } \\ & \angle ORQ=\angle OQR=2{{x}^{\circ }}\text{ }\!\!\{\!\!\text{ base }\angle s\text{ of Isso }\vartriangle \} \\ & \angle ROQ+\angle ORQ+\angle OQR={{180}^{\circ }}\text{ } \\ & \text{ }\!\!\{\!\!\text{ sum of }\angle s\text{ in a }\vartriangle \} \\ & {{124}^{\circ }}+2{{x}^{\circ }}+2{{x}^{\circ }}={{180}^{\circ }} \\ & 4{{x}^{\circ }}={{56}^{\circ }} \\ & x={{14}^{\circ }} \\\end{align}\]Alternatively method\[\begin{align} & \angle ORQ+\angle OQR=\angle POR \\ & \{sum\text{ o}f\text{ two opp int }\angle s=\angle \text{ of a }\vartriangle \} \\ & 2x+2x={{56}^{\circ }} \\ & x={{14}^{\circ }} \\\end{align}\]
