Jambmaths question:
if $y=6{{x}^{3}}+2{{x}^{-2}}-{{x}^{-3}}$ find $\frac{dy}{dx}$
Option A:
$\frac{dy}{dx}=15{{x}^{2}}-4{{x}^{-2}}-3{{x}^{-2}}$
Option B:
$\frac{dy}{dx}=6x+4{{x}^{-1}}-3{{x}^{-4}}$
Option C:
$\frac{dy}{dx}=18{{x}^{2}}-4{{x}^{-3}}+3{{x}^{-4}}$
Option D:
$12{{x}^{2}}+4{{x}^{-1}}-3{{x}^{-2}}$
Jamb Maths Solution:
$\begin{align} & y=6{{x}^{3}}+2{{x}^{-2}}-{{x}^{-3}} \\ & \frac{dy}{dx}=18{{x}^{3-1}}+2{{x}^{-2-1}}-(-3){{x}^{-3-1}} \\ & \frac{dy}{dx}=18{{x}^{2}}+2{{x}^{-3}}+3{{x}^{-4}} \\\end{align}$
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