Jambmaths question:
If $4{{\sin }^{2}}x-3=0$ find the value of x when $0{}^\circ \le x\le 90{}^\circ $
Option A:
90o
Option B:
45o
Option C:
60o
Option D:
30o
Jamb Maths Solution:
$\begin{align} & 4{{\sin }^{2}}x-3=0 \\ & 4{{\sin }^{2}}x=3 \\ & {{\sin }^{2}}x=\frac{3}{4} \\ & \sin x=\sqrt{\frac{3}{4}}=\frac{\sqrt{3}}{2} \\ & x={{\sin }^{-1}}\frac{\sqrt{3}}{2}=60{}^\circ \\\end{align}$
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