Jambmaths question:
Given $\sin 58{}^\circ =\cos p{}^\circ $ find p
Option A:
48
Option B:
58
Option C:
32
Option D:
52
Jamb Maths Solution:
$\begin{align} & \sin 58{}^\circ =\cos p{}^\circ \\ & \sin \theta =\cos (90{}^\circ -\theta ) \\ & sin58{}^\circ =\cos (90-58{}^\circ ) \\ & \sin 58{}^\circ =\cos 32{}^\circ \\ & p=32 \\\end{align}$
Jamb Maths Topic:
Year of Exam: