Jambmaths question:
Simplify $\frac{1\tfrac{1}{3}+\tfrac{1}{2}\text{ of }6}{\tfrac{1}{3}\times 15\div \tfrac{5}{3}}$
Option A:
$\tfrac{3}{10}$
Option B:
$\tfrac{9}{10}$
Option C:
$\tfrac{10}{9}$
Option D:
$\tfrac{13}{9}$
Jamb Maths Solution:
$\frac{1\tfrac{1}{3}+\tfrac{1}{2}\text{ of }6}{\tfrac{1}{3}\times 15\div \tfrac{5}{3}}=\frac{\tfrac{4}{3}+3}{\tfrac{1}{3}\times 15\times \tfrac{3}{5}}=\frac{\tfrac{13}{3}}{3}=\frac{13}{9}$
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