waecmaths question:
|
Number of goals |
1 |
2 |
3 |
4 |
5 |
6 |
7 |
|
Number of teams |
3 |
1 |
6 |
6 |
4 |
2 |
3 |
The table shows the distribution of goal scored by 25 teams in a football competition.
Calculate the probability that a team selected at random scored at most 3 goals
Option A:
$\tfrac{3}{25}$
Option B:
$\tfrac{1}{5}$
Option C:
$\tfrac{6}{25}$
Option D:
$\tfrac{2}{5}$
waecmaths solution:
Total (Teams with almost of almost 3 goals) = 3+1+6 =10
Total number of teams = 25
$\Pr (at\text{most three goals)}=\frac{10}{25}=\frac{2}{5}$
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