Jambmaths question:
From the top of a tree, the angle of depression to a point on the ground 5m away is 60o. Find the height of the tree.
Option A:
$5\sqrt{3}m$
Option B:
$\sqrt{55}m$
Option C:
$4\sqrt{5}m$
Option D:
$\sqrt{60}m$
Jamb Maths Solution:
$\angle BCA=60{}^\circ \text{ }\!\!\{\!\!\text{ Alternate angles }\!\!\}\!\!\text{ }$
$\tan 60{}^\circ =\frac{AB}{BC}=\frac{AB}{5}$
$\sqrt{3}=\frac{AB}{5m}$
$AB=5\sqrt{3}m$
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