Jambmaths question:
Find the mean of the distribution
|
X |
21 |
22 |
23 |
24 |
25 |
26 |
36 |
|
F |
3 |
4 |
2 |
6 |
1 |
1 |
3 |
Option A:
20
Option B:
23
Option C:
25
Option D:
21
Jamb Maths Solution:
$\begin{align} & \bar{x}=\frac{\left[ (21\times 3)+(22\times 4)+(23\times 2)+(24\times 6)+(25\times 1)+(26\times 1)+(36\times 3) \right]}{3+4+2+6+1+1+3} \\ & \bar{x}=\frac{63+88+46+144+25+26+108}{20}=\frac{500}{20} \\ & \bar{x}=25 \\\end{align}$
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