Jambmaths question:
Find$\frac{dy}{dx}$ , if $y=\tfrac{2}{3}{{x}^{3}}-\tfrac{4}{x}$
Option A:
$3{{x}^{2}}-\tfrac{4}{{{x}^{2}}}$
Option B:
$2{{x}^{2}}+\tfrac{4}{{{x}^{2}}}$
Option C:
$3{{x}^{2}}+\tfrac{4}{{{x}^{2}}}$
Option D:
$2{{x}^{2}}-\tfrac{4}{{{x}^{2}}}$
Jamb Maths Solution:
$\begin{align} & y=\tfrac{2}{3}{{x}^{3}}-\tfrac{4}{x}=\tfrac{2}{3}{{x}^{3}}-4{{x}^{-1}} \\ & \frac{dy}{dx}=2{{x}^{2}}+4{{x}^{-2}}=2{{x}^{2}}+\tfrac{4}{{{x}^{2}}} \\\end{align}$
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