Jambmaths question:
Factorize ${{k}^{2}}-2kp+{{p}^{2}}$${{(k+p)}^{2}}$
Option A:
${{(k-p)}^{2}}$
Option B:
${{k}^{2}}+{{p}^{2}}$
Option C:
${{k}^{2}}-{{p}^{2}}$
Option D:
${{k}^{2}}-{{p}^{2}}$
Jamb Maths Solution:
$\begin{align} & {{k}^{2}}-2kp+{{p}^{2}}=k-kp-kp+{{p}^{2}} \\ & {{k}^{2}}-2kp+{{p}^{2}}=k(k-p)-p(k-p) \\ & {{k}^{2}}-2kp+{{p}^{2}}=(k-p)(k-p)={{(k-p)}^{2}} \\\end{align}$
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