Maths Question:
$\begin{align} & \text{Find the equation whose roots are numerically equal to those of }2{{x}^{2}}+2x-12=0 \\ & \text{but of opposite signs} \\\end{align}$
Maths Solution:
$\begin{align} & \text{The given equation }2{{x}^{2}}+2x-12=0 \\ & \text{we determine the roots of }2{{x}^{2}}+2x-12=0 \\ & 2({{x}^{2}}+x-6)=0 \\ & 2(x+3)(x-2)=0 \\ & x=-3,x=2 \\ & \text{The required equation will be } \\ & (x+3)(x-2)=0 \\ & {{x}^{2}}-x+6=0 \\\end{align}$
University mathstopic: