waecmaths question:
The angle of elevation of the top of a cliff 15metres is 60o. How far is the landmark from the foot of the cliff. Leave your answer in surd form
Option A:
$15\sqrt{3}m$
Option B:
$15\sqrt{2}m$
Option C:
$10\sqrt{3}m$
Option D:
$5\sqrt{3}m$
waecmaths solution:
$\begin{align} & \tan \theta =\frac{opp}{hyp} \\ & \tan {{60}^{\circ }}=\frac{CB}{AB} \\ & \sqrt{3}=\frac{15}{AB} \\ & AB=\frac{15}{\sqrt{3}}=\frac{15\sqrt{3}}{\sqrt{3}\times \sqrt{3}}=\frac{15\sqrt{3}}{3}=5\sqrt{3} \\\end{align}$
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