Jambmaths question:
Given that
M = {x : x is prime and $7\le x\le 13$}and
R = {y: y is a multiple of 3 and $6<y\le 15$}, find $M\cup R$
Option A:
{6,7,9, 11, 12, 12, 15}
Option B:
{7, 9, 11, 12}
Option C:
{7, 9, 11, 12, 13, 15}
Option D:
{6,7, 9, 11, 15}
Jamb Maths Solution:
$\begin{align} & M=\{7,11,13\} \\ & R=\{9,12,15\} \\ & M\cup R=\{7,9,11,12,13,15\} \\\end{align}$
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