Jambmaths question:
Solve the inequality $(x+4)(x+1)\le 0$
Option A:
$4\le x\le -1$
Option B:
$1\le x\le 4$
Option C:
$-4\le x\le -1$
Option D:
$-1\le x\le 4$
Jamb Maths Solution:
We use the inequality table to determine the range
|
|
x$\le $-4 |
-4$\le $ x$\le $ -1 |
x$\ge $ -1 |
|
(x+4) |
-ve |
+ve |
+ve |
|
(x+1) |
-ve |
-ve |
+ve |
|
(x+4)(x+1) |
+ve |
-ve |
+ve |
The range is $-4\le x\le -1$
$(x+4)(x+1)\le 0$
Jamb Maths Topic:
Year of Exam: