Jambmaths question:
If $y={{x}^{2}}-3x+4$ find $\tfrac{dy}{dx}$ at x = 5
Option A:
3
Option B:
5
Option C:
7
Option D:
9
Jamb Maths Solution:
$\begin{align} & y={{x}^{2}}-3x+4 \\ & \frac{dy}{dx}=2x-3 \\ & \text{At }x=5 \\ & {{\left. \frac{dy}{dx} \right|}_{x=5}}=2(5)-3=7 \\\end{align}$
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