Jambmaths question:
Find the value of X in the figure above
Option A:
$4\sqrt{3}cm$
Option B:
$5\sqrt{3}cm$
Option C:
$10\sqrt{3}cm$
Option D:
$20\sqrt{3}cm$
Jamb Maths Solution:
$\begin{align} & \text{Using the sine rule} \\ & \frac{10cm}{\sin {{30}^{\text{o}}}}=\frac{x}{\sin {{60}^{\text{o}}}} \\ & x=\frac{10cm\times \sin {{60}^{\circ }}}{\sin {{30}^{\circ }}}=\frac{10cm\times \tfrac{\sqrt{3}}{2}}{\tfrac{1}{2}} \\ & x=\frac{10\times \sqrt{3}\times 2}{2}=10\sqrt{3}cm \\\end{align}$
Jamb Maths Topic:
Year of Exam:
